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PhysicsEMI/ACSeries AC CircuitsMedium2 minQB

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In L-R series circuit, source voltage is 10V and voltage across R is 8V. Phase difference ( $ϕ$ ) between applied voltage and current is:

Answer:

Solution:

The resistor voltage is in phase with the current.

$cos ϕ = \frac{V _{R}}{V} = \frac{8}{10} = \frac{4}{5}$

$sin ϕ = \frac{3}{5}, tan ϕ = \frac{3}{4}$

$ϕ = tan^{- 1} (\frac{3}{4})$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: QB

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