Physics - EMI/AC Question with Solution | TestHub

Given $L=1\text{ mH}=10^{-3}\text{ H}$ and $C=0.1\mu \text{F}=10^{-7}\text{ F}$.

The resonance frequency of a series RLC circuit is given by $f_r=\frac{1}{2\pi \sqrt{LC}}$.

Substituting the values:

$f_r=\frac{1}{2\pi \sqrt{10^{-3}\times 10^{-7}}}$

$f_r=\frac{1}{2\pi \sqrt{10^{-10}}}$

$f_r=\frac{10^5}{2\pi }\text{ Hz}$

$f_r=\frac{50}{\pi }\text{ kHz}\approx 15.9\text{ kHz}$

Answer: $15.9$ kHz