Physics - EMI/AC Question with Solution | TestHub

The alternating current is given by $I=I_0\sin (\omega t)$.

The time taken to reach the peak value from zero corresponds to a phase angle of $\frac{\pi }{2}$.

$\omega t=\frac{\pi }{2}$

$2\pi ft=\frac{\pi }{2}$

$t=\frac{1}{4f}$

Given $f=60$ Hz, we get:

$t=\frac{1}{4\times 60}=\frac{1}{240}$ s.

Answer: $\frac{1}{240}$ s