A uniform magnetic field of 0.4 T acts perpendicular to a circular copper disc 20 cm in radius. The disc is having a uniform angular velocity of 10 π rad s − 1 about an axis through its centre and per

Question

A uniform magnetic field of 0.4 T acts perpendicular to a circular copper disc 20 cm in radius. The disc is having a uniform angular velocity of $10 π rad s^{- 1}$ about an axis through its centre and perpendicular to the disc. What is the potential difference developed between the axis of the disc and the rim ? $(π = 3.14)$

Options:

Answer:

C

Solution:

$B = 0.4 T r = 20 cm ω = 10 π rad / s E = \frac{1}{2} B ω R^{2} = 0.2512 V$

TestHub · Accepted Answer

​ B = 0.4 T r = 20 cm ω = 10 π rad / s E = 2 1 ​ B ω R 2 = 0.2512 V ​

Physics - EMI/AC Question with Solution | TestHub

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