A rectangular loop of length 2 . 5 m and width 2 m is placed at 60 ° to a magnetic field of 4 T . The loop is removed from the field in 10 sec . The average emf induced in the loop during this time is

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The formula to calculate the change in the magnetic flux associated with the given loop can be written as

$\begin{array}{rcl} ∆ ϕ & = & - B A \cos θ \\ = & - B (l b) \cos θ . . . (1) \end{array}$

The formula to calculate the induced emf is given by

$\begin{array}{rcl} ε & = & - \frac{∆ ϕ}{∆ t} \\ = & \frac{B (l b) \cos θ}{∆ t} . . . (2) \end{array}$

From equation (2), it follows that

$\begin{array}{rcl} ε & = & \frac{4 \times (2.5 \times 2) \times \cos 60 °}{10} V \\ = & 1 V \end{array}$

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