Physics - EMI/AC Question with Solution | TestHub

Given here, $\frac{\mathrm{d}I}{\mathrm{d}t}=-1 \mathrm{A} {\mathrm{s}}^{-1}$

Applying Kirchhoff's voltage law to the circuit,

$V_A-IR-L\frac{\mathrm{d}I}{\mathrm{d}t}-12=V_B$

$\Rightarrow V_A-2\times 12-6(-1)-12=V_B$

$\Rightarrow V_{AB}=V_A-V_B=36-6=30 \mathrm{V}$