A series LCR circuit consists of R = 80 Ω . X L = 100 Ω , and X C = 40 Ω . The input voltage is 2500 cos 100 π t V . The amplitude of current, in the circuit, is _____ A .

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TestHub · Accepted Answer

Comparing input voltage with standard expression, $V = V_{0} \cos (ω t)$ , we get $ω = 100 π$ .

Now, impedance $Z = \sqrt{R^{2} + {(X_{L} - X_{C})}^{2}}$

$= \sqrt{80^{2} + {(100 - 40)}^{2}}$

$= 100 Ω$

Therefore, peak current

$i_{0} = \frac{V_{0}}{Z} = \frac{2500}{100} A = 25 A$

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