Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACMotional & Rotational EMFEasy2 minPYQ_2021

PhysicsEasynumerical

A circular coil of radius $8.0 cm$ and $20$ turns is rotated about its vertical diameter with an angular speed of $50 rad s^{- 1}$ in a uniform horizontal magnetic field of $3.0 \times 10^{- 2} T$ . The maximum emf induced in the coil will be _______ $\times 10^{- 2}$ volt (rounded off to the nearest integer).

Answer:

60.00

Solution:

$Emf = B ω NAsin ω t$

${Emf}_{\max} = BωNA = BωN ({πR}^{2})$

$= (3 \times 10^{- 2}) \times (50) \times (20) \times (π \times \frac{64}{10^{4}}) \approx 60 \times 10^{- 2} V$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Motional & Rotational EMF

⏱ 2mℹ️ Source: PYQ_2021

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