A current of 5 A is flowing at 220 V in the primary coil of a transformer. If the voltage produced in the secondary coil is 2200 V and 50 % of power is lost, then the current in the secondary coil is

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Given, power output = 1 2 × power input (or 50 % of input power) ∴ I s V s = 1 2 I p ⋅ V p ∵ P = V I Here, I p = 5 A , V p = 220 V and V s = 2200 V ∴ I s = I p ⋅ V p 2 V s = 5 × 220 2 × 2200 = 0. 25 A

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