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PhysicsEMI/ACSelf and mutual inductorEasy2 minPYQ_2020

PhysicsEasysingle choice

A coil of wire of radius $r$ has $600$ turns and self-inductance of $108 mH$ . The self-inductance of a coil with the same radius and $500$ turns is

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Answer:

Solution:

Given $L_{1} = 108 m H, N_{1} = 600 t u r n s, N_{2} = 500 t u r n s a n d L_{2} = ?$

By self - inductance of a plane coil

$L_{1} = \frac{μ_{0} π N_{1}^{2} a_{1}}{2}$ ......(i)

$L_{2} = \frac{μ_{0} π N_{2}^{2} a_{2}}{2}$ ......(ii)

From the equations (i) and (ii), we get

$\frac{L_{1}}{L_{2}} = {(\frac{N_{1}}{N_{2}})}^{2}$ $(∵ a_{1} = a_{2})$

$\frac{108}{L_{2}} = {(\frac{600}{500})}^{2}$

$L_{2} = \frac{108 \times 25}{36}$

$L_{2} = 3 \times 25 = 75 m H$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:EMI/ACSubtopic:Self and mutual inductor

⏱ 2mℹ️ Source: PYQ_2020

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