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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSeries AC CircuitsEasy2 minPYQ_2020

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An oscillator circuit contains an inductor $0 .05 H$ and a capacitor of capacity $80 μF$ . When the maximum voltage across the capacitor is $200 V$ , the maximum current (in amperes) in the circuit is

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Answer:

Solution:

Given $L = 0. 05 H, C = 80 μF$

$V_{m a x} = 200 V$

$∵$ Voltage equation $V (t) = V_{m} \sin ω t$

$∴$ Current (i) $= \frac{c d v}{d t} = c \frac{d}{d t} V_{m} \sin ω t = C V_{m} ω \cos ω t$

$∵ ω = \frac{1}{\sqrt{L C}}$

$∴ i = V_{m} \sqrt{\frac{C}{L}} \cos ω t$

$∴$ Maximum current $(i_{m}), V_{m} \sqrt{\frac{C}{L}} = 200 \times \sqrt{\frac{80 μ}{0.05}}$

$i_{m} = 8 A$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2020

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