A circular disc of the radius 0 . 2 m is placed in a uniform magnetic field of induction 1 π Wb m − 2 in such a way that its axis makes an angle of 60 ° with B → . The magnetic flux linked with the disc is

B = 1 π Wb m - 2 Area of the disc normal to B is π R 2 cos 6 0 ∘ . Flux = B x Area normal to the magnetic field ∴ Flux = 1 π × π × 0.04 × 1 2 = 0.02 Wb

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PhysicsEMI/ACFaraday law/Lenz lawEasy2 minPYQ_2020

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A circular disc of the radius $0.2 m$ is placed in a uniform magnetic field of induction $\frac{1}{π} Wb m^{- 2}$ in such a way that its axis makes an angle of $60 °$ with $\vec{B}$ . The magnetic flux linked with the disc is

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Answer:

Solution:

$B = \frac{1}{π} Wb m^{- 2}$

Area of the disc normal to B is $π R^{2} cos 6 0^{\circ}$ .

Flux = $B$ x Area normal to the magnetic field

$∴$ $Flux = \frac{1}{π} \times π \times 0.04 \times \frac{1}{2} = 0.02 Wb$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:EMI/ACSubtopic:Faraday law/Lenz law

⏱ 2mℹ️ Source: PYQ_2020

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