Physics - EMI/AC Question with Solution | TestHub

In series LCR, the current is maximum at resonance.

$\therefore$Resonant frequency,$\omega =\frac{1}{\sqrt{\mathit{\text{LC}}}}$

$\therefore$${\omega }^2=\frac{1}{\mathit{\text{LC}}}$or,$\mathit{\text{L}}=\frac{1}{{\omega }^2\mathit{\text{C}}}$

Given,$\omega =1000{\text{ s}}^{-1}$and$\text{C}=1\mathrm{0 }\mu \text{F}$

$\therefore$$\mathit{\text{L}}=\frac{1}{1000\times 1000\times 10\times 10^{-6}}=\text{0.1}\text{ H}=100\text{ mH}$