Physics - EMI/AC Question with Solution | TestHub

Given,

Output of step down transformer$\left(V_s\right)=48 V$

Power associated with secondary coil$\left(P_s\right)=12 W$

$I_s=\frac{P_s}{V_s}=\frac{12}{48}=\frac{1}{4}=0.25 A$

Amplitude of current$\left(I_0\right)=I_s\sqrt{2}$

$=0.25 \left(\sqrt{2}\right)$

$=\frac{\sqrt{2}}{4}$

$=\frac{1}{2\sqrt{2}}A$