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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACFaraday law/Lenz lawMedium2 minPYQ_2020

PhysicsMediumsingle choice

A conducting loop (as shown) has total resistance $R$ . A uniform magnetic field $B = γ t$ is applied perpendicular to plane of the loop where $γ$ is a constant and $t$ is time. The induced current flowing through loop is

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Answer:

Solution:

Given,

Uniform magnetic field $(B) = γ t$

Total flux, $\vec{B_{1}} . \vec{A_{1}} + \vec{B_{2}} . \vec{A_{2}}$

$= B b^{2} \cos 0^{o} + B a^{2} \cos 180^{o}$

$= B b^{2} - B a^{2}$

$ϕ = B (b^{2} - a^{2})$

$ϕ = γ t (b^{2} - a^{2})$

We know that,

Induced current (i) $= \frac{|e|}{R} = \frac{|\frac{d ϕ}{d t}|}{R}$

From Equation (i),

$(i) = \frac{\frac{d}{d t} [γ t (b^{2} - a^{2})]}{R}$

$(i) = \frac{(b^{2} - a^{2}) γ}{R}$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Faraday law/Lenz law

⏱ 2mℹ️ Source: PYQ_2020

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