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PhysicsEMI/ACSelf and mutual inductorEasy2 minPYQ_2020

PhysicsEasysingle choice

Two concentric co-planar circular loops of radius $R$ and $r (< < R)$ are placed as shown in the figure. The mutual inductance of the system will be

Answer:

Solution:

The magnetic flux through the smaller loop due to the bigger loop is

$ϕ_{21} = (\frac{μ_{0} i}{2 R}) \times π r^{2}$

$\Rightarrow M = \frac{ϕ_{21}}{i} = (\frac{π μ_{0} r^{2}}{2 R})$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:EMI/ACSubtopic:Self and mutual inductor

⏱ 2mℹ️ Source: PYQ_2020

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