Physics - EMI/AC Question with Solution | TestHub

If we flow a current $i$, then $\begin{array}{rl}& {\varphi }_{\text{self }}=(B\times A)\times N=\left(\frac{{\mu }_{0}Ni}{2\pi R}\right)A\times N\\ & \Rightarrow {\varphi }_{\text{self }}=\left(\frac{{\mu }_0{N}^{2}A}{2\pi R}\right)i\text{ and }{\varphi }_{\text{self }}=Li\end{array}$ $\begin{array}{rl}& L=\frac{{\mu }_0{N}^{2}A}{2\pi R}=\frac{{\mu }_0}{4\pi }\frac{2N^{2}A}{R}\\ & \Rightarrow L=\left(10^{-7}\right)\times \frac{2\times (500{)}^2\times 10\times {\left(10^{-2}\right)}^2}{0.4}\\ & =125\mu \mathrm{H}\end{array}$