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PhysicsEMI/ACSeries AC CircuitsEasy2 minPYQ_2018

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An alternating voltage of $220 V, 50 Hz$ frequency is applied across a capacitor of capacitance $2 μ F$ . The impedence of the circuit is

Answer:

Solution:

Impedence of a capacitor is $X_{C} = 1/ ω C$ $X_{C} = \frac{1}{2 π fC} = \frac{1}{2 π \times 50 \times 2 \times 1 0 ^{- 6}} = \frac{5000}{π}$

Stream:VITEEESubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2018

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