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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACTransformerEasy2 minPYQ_2017

PhysicsEasysingle choice

A transformer with efficiency $80%$ works at $4 kW$ and $100 V$ . If the secondary voltage is $200 V$ , then the primary and secondary currents are respectively

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Solution:

$(a) : Here, η = 80% P_{i} = 4 kW = 4000 W V_{p} = 100 V, V_{s} = 200 V I_{p} = \frac{P _{i}}{V _{p}} = \frac{4000}{100} = 40 A η = \frac{V _{s} I _{s}}{V _{p} I _{p}}; \frac{80}{100} = \frac{200 I _{s}}{4000} = \frac{I _{s}}{20} or I_{s} = \frac{20 \times 80}{100} = 16 A$

Stream:AIIMSSubject:PhysicsTopic:EMI/ACSubtopic:Transformer

⏱ 2mℹ️ Source: PYQ_2017

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