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PhysicsEMI/ACSeries AC CircuitsEasy2 minPYQ_2016

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A series resonant $L CR$ circuit has a quality factor (Q-factor) 0.4 . If $R = 2 k Ω, C = 0.1 μ F$ , then the value of inductance is

Answer:

Solution:

$Q = \frac{1}{R} \frac{L}{C} or \frac{L}{C} = (QR)^{2} ∴ L = (0.4 \times 2 \times 1 0^{3})^{2} \times 0.1 \times 1 0^{- 6} = 0.064 H$

Stream:AIIMSSubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2016

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