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PhysicsEMI/ACSeries AC CircuitsMedium2 minPYQ_2016

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A $100 Ω$ resistance and a capacitor of $100 Ω$ reactance are connected in series across a $220 V$ source. When the capacitor is $50 %$ charged, the peak value of the displacement current isNEET 2016 (Phase 2)

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Answer:

Solution:

Given, $R = 100 Ω$ , $X_{C} = 100 Ω$ .

$Z = \sqrt{X_{C}^{2} + R^{2}}$ $= 100 \sqrt{2} Ω$ .

$V_{\max} = 220 \sqrt{2} V$ .

$I_{\max} = \frac{V_{\max}}{Z}$ $= \frac{220 \sqrt{2}}{100 \sqrt{2}} = 2.2 A$ .

Stream:NEETSubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2016

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