Physics - EMI/AC Question with Solution | TestHub

Maximum current flows in the circuit in resonance condition Current in the LCR circuit $i=\frac{V}{\sqrt{R^2+{\left(X_L-X_C\right)}^2}}$ For current to be maximum denominator should be minimum ${\left(X_L-X_C\right)}^2=0$ $\begin{array}{l}\Rightarrow {\mathrm{X}}_{\mathrm{L}}={\mathrm{X}}_{\mathrm{C}}\Rightarrow \omega \mathrm{L}=\frac{1}{\omega \mathrm{C}}\\ \therefore \mathrm{L}=\frac{1}{{\omega }^2\mathrm{C}}=\frac{1}{(100{)}^2\times 10\times 10^{-6}}\\ \mathrm{L}=\frac{1}{10}\mathrm{H}=0.1\mathrm{H}=100\mathrm{mH}\end{array}$