A coil of area 5 cm 2 having 20 turns is placed in a uniform magnetic field of 1 0 3 gauss. The normal to the plane of coil makes an angle 3 0 ∘ with the magnetic field. The flux through the coil is

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Given : N = 20 B = 1 0 3 gauss = 1 0 3 × 1 0 − 4 T = 0.1 T A = 5 cm 2 = 5 × 1 0 − 4 m 2 θ = 8 0 ∘ ​ ∴ Flux through the coil ϕ = NBA cos θ = 20 × 0.1 × 5 × 1 0 − 4 × cos 3 0 ∘ ​ = 10 × 1 0 − 4 × 2 3 ​ ​ = 5 3 ​ × 1 0 − 4 = 865 × 1 0 − 4 wb ​

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