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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSeries AC CircuitsEasy2 minPYQ_2011

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An AC voltage is applied to a resistance $R$ and an inductor $L$ in series. If $R$ and the inductive reactance are both equal to $3Ω$ , the phase difference between the applied voltage and the current in the circuit isNEET 2011 (Screening)

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Answer:

Solution:

$tan ϕ = \frac{X _{L}}{R} tan ϕ tan ϕ ϕ ϕ ϕ = \frac{L ω}{R} = \frac{3Ω}{3Ω} = 1 = tan^{- 1} (1) = 4 5^{\circ} = \frac{π}{4} rad$

Stream:NEETSubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2011

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