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PhysicsEMI/ACSeries AC CircuitsEasy2 minPYQ_2002

PhysicsEasysingle choice

For a series LCR circuit the power loss at resonance is:NEET 2002

Answer:

Solution:

Power loss is given by $P = V I cos ϕ$ At resonance current and voltage are in the same phase, that is $ϕ = 0$ . $∴ P = V I cos 0 = V I = I^{2} R$

Stream:NEETSubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2002

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