A rectangular coil of 100 turns, area 20 cm 2 , rotates at 1500 revolutions per minute in a uniform magnetic field of 0.1 T. The axis of rotation is perpendicular to the magnetic field. Calculate the

Question

A rectangular coil of 100 turns, area 20 cm 2 , rotates at 1500 revolutions per minute in a uniform magnetic field of 0.1 T. The axis of rotation is perpendicular to the magnetic field. Calculate the peak induced electromotive force (EMF) in volts. (Take π = 3.14 ) (Round to the nearest integer)

TestHub · Accepted Answer

The peak induced EMF in a rotating coil is given by $EMF_{p e ak} = NB A ω$ .

First, convert the rotation speed to angular frequency: $ω = 2 π f$ .

Given $f = 1500 rpm = \frac{1500}{60} rps = 25 rps$ .

So, $ω = 2 π (25) = 50 π rad/s$ .

Given $N = 100$ , $B = 0.1 T$ ,

and $A = 20 cm^{2} = 20 \times 1 0^{- 4} m^{2} = 0.002 m^{2}$ . $EMF_{p e ak} = (100) (0.1 T) (0.002 m^{2}) (50 π rad/s) = 10 \times 0.002 \times 50 π V = 1 π V$ .

Using $π = 3.14$ , $EMF_{p e ak} = 3.14 V$ .

Rounding to the nearest integer gives 3.

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