Physics - EMI/AC Question with Solution | TestHub

For a damped simple harmonic motion, the angular frequency ${\omega }^{\prime }$ is given by ${\omega }^{\prime }=\sqrt{{\omega }_0^2-(b/2m{)}^2}$, where ${\omega }_0$ is the natural angular frequency in the absence of damping, $b$ is the damping coefficient, and $m$ is the mass. Since ${\omega }^{\prime }<{\omega }_0$, the new time period $T^{\prime }=2\pi /{\omega }^{\prime }$ will be greater than the original time period $T_0=2\pi /{\omega }_0$. Thus, the time period of oscillation increases slightly due to damping.