A time varying potential difference is applied between the plates of a parallel plate capacitor of capacitance 2.5 μ F . The dielectric constant of the medium between the capacitor plates is 1 . It pr

Question

A time varying potential difference is applied between the plates of a parallel plate capacitor of capacitance $2.5 μ F$ . The dielectric constant of the medium between the capacitor plates is 1 . It produces an instantaneous displacement current of 0.25 mA in the intervening space between the capacitor plates, the magnitude of the rate of change of the potential difference will be _____ $Vs^{- 1}$ .

Answer:

100.00

Solution:

$\frac{CdV}{dt} = I_{d} \frac{dV}{dt} = \frac{I _{d}}{C} = \frac{0.25 \times 1 0 ^{- 3}}{2.5 \times 1 0 ^{- 6}} = 100$

TestHub · Accepted Answer

​ dt CdV ​ = I d ​ dt dV ​ = C I d ​ ​ = 2.5 × 1 0 − 6 0.25 × 1 0 − 3 ​ = 100 ​

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