Physics - EM Waves Question with Solution | TestHub

$\overrightarrow{\mathrm{E}}=\hat{\mathrm{i}}40\cos \omega \left(\mathrm{t}-\frac{\mathrm{z}}{\mathrm{c}}\right)$ $\overrightarrow{\mathrm{E}}$ is along $+\mathrm{x}$ direction $\overrightarrow{\mathrm{v}}$ is along $+\mathrm{z}$ direction So direction of $\vec{B}$ will be along +y and magnitude of $B$ will be $\frac{E}{c}$ So answer is $\frac{40}{c}\cos \omega \left(t-\frac{z}{c}\right)\hat{j}$