Physics - EM Waves Question with Solution | TestHub

PhysicsEM WavesElectromagnetic wavesEasy2 minPYQ_2023
PhysicsEasysingle choice

In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of2.0×1010 Hzand amplitude48 V m-1. Then the amplitude of oscillating magnetic field is: (Speed of light in free space = 3×108 m s-1)NEET 2023 (All India)

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Answer:
D
Solution:

Frequency of oscillation =2×1010 Hz
Given c=3×108 m s-1,

Electric field amplitude E0=48 V m-1

Using the formula, c=E0B0

The amplitude of the oscillating magnetic field

B⁡0=E⁡0c=483×108=1.6×10-7 T.

Stream:NEETSubject:PhysicsTopic:EM WavesSubtopic:Electromagnetic waves
⏱ 2mℹ️ Source: PYQ_2023

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