Physics - EM Waves Question with Solution | TestHub

The magnetic field vector of an electromagnetic wave is given by$B=B_0\frac{\hat{\mathrm{i}}+\hat{\mathrm{j}}}{\sqrt{2}}\cos \left(kz-\omega t\right)$where$\hat{\mathrm{i}}, \hat{\mathrm{j}}$represents unit vector along$x$and$y$-axis respectively. At$t=0 \mathrm{s},$two electric charges$q_1$of$4\pi$coulomb and$q_2$of$2\pi$coulomb located at$\left(0, 0, \frac{\pi }{k}\right)$and$\left(0, 0, \frac{3\pi }{k}\right),$respectively, have the same velocity of$0.5\mathrm{c}\hat{\mathrm{i}},$(where$c$is the velocity of light ). The ratio of the force acting on charge$q_1$to$q_2$is :