Physics - EM Waves Question with Solution | TestHub

PhysicsEM WavesElectromagnetic wavesEasy2 minPYQ_2020

PhysicsEasysingle choice

In an electromagnetic wave, the maximum value of the electric field is $100 V m^{- 1}$ . The average intensity is [ $ε_{0} = 8.8 \times 10^{- 12} C^{- 2} N^{- 1} m^{2}$ ]

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Answer:

Solution:

$I_{avg} = \frac{1}{2} c ε_{0} {(E_{0})}^{2}$

$\Rightarrow I_{avg} = \frac{1}{2} \times 3 \times 10^{8} \times 8.8 \times 10^{- 12} \times {(100)}^{2}$

$\Rightarrow I_{avg} = 13.2 W m^{- 2}$

Subject:PhysicsTopic:EM WavesSubtopic:Electromagnetic waves

⏱ 2mℹ️ Source: PYQ_2020

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