Physics - EM Waves Question with Solution | TestHub

PhysicsEM WavesElectromagnetic wavesMedium2 minPYQ_2020

PhysicsMediumnumerical

A proton, when accelerated through a potential difference of $V = 29.6 V$ , has a wavelength $λ$ associated with it. An $α -$ particle, in order to have the same $λ$ , must be accelerated through a potential difference of how many volts?

Answer:

3.70

Solution:

$λ_{P} = λ_{α}$

$o r \frac{h}{\sqrt{2 m_{p} Q_{P} V_{p}}} = \frac{h}{\sqrt{2 m_{α} Q_{α} V_{α}}}$

$∴ m_{p} Q_{p} V_{p} = m_{α} Q_{α} V_{α}$

$∴ V_{α} = (\frac{m_{p}}{m_{α}}) (\frac{Q_{p}}{Q_{α}}) V_{p}$

$\Rightarrow V_{α} = (\frac{1}{4}) (\frac{1}{2}) \times 29.6 V = 3.7 V$

Subject:PhysicsTopic:EM WavesSubtopic:Electromagnetic waves

⏱ 2mℹ️ Source: PYQ_2020

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