Physics - EM Waves Question with Solution | TestHub

$f=10^{14}\text{ Hz}$
$E_0=4\text{V/m}$
${\in }_0=\text{8.8}\times 10^{-12}\frac{{\text{C}}^2}{\text{N}-{\text{m}}^2}$
Energy density of electric field
=$\frac{1}{2}$(Total energy density)
$=\frac{1}{2}·\frac{1}{2}{\in }_0{\text{E}}^2$
$=\frac{1}{2}\text{.}\frac{1}{2}\left\{\text{8.8}\times 10^{-12}\times 4^2\right\}$
$=\frac{1}{2}·\frac{1}{2}\times 16\times 8.8\times {10}^{-12}{\text{J/m}}^3$
$=35.2\times {10}^{-12}{\text{J/m}}^3$