Physics - EM Waves Question with Solution | TestHub

$\overrightarrow{\mathrm{B}}={\mathrm{B}}_0\widehat{\mathrm{i}}\left[\mathrm{c}\mathrm{o}\mathrm{s}\left(\mathrm{k}\mathrm{z}-\mathrm{\omega }\mathrm{t}\right)\right]+{\mathrm{B}}_1\widehat{\mathrm{j}}\mathrm{c}\mathrm{o}\mathrm{s}\left(\mathrm{k}\mathrm{z}+\mathrm{\omega }\mathrm{t}\right)$
${\mathrm{B}}_0=3\times {10}^{-5}\mathrm{ }\mathrm{T}\mathrm{ }\& {\mathrm{B}}_1=2\times {10}^{-6} \mathrm{T}$
Electric filed associated with it is,
$\overrightarrow{\mathrm{E}}=-{\mathrm{B}}_0\mathrm{c}\widehat{\mathrm{j}}\mathrm{c}\mathrm{o}\mathrm{s}\left(\mathrm{k}\mathrm{z}-\mathrm{\omega }\mathrm{t}\right)-{\mathrm{B}}_1\mathrm{c}\widehat{\mathrm{i}}\mathrm{c}\mathrm{o}\mathrm{s}\left(\mathrm{k}\mathrm{z}+\mathrm{\omega }\mathrm{t}\right)$
Here,$c$is the speed of light in vacuum.
At$\mathrm{z}=0,$
${\mathrm{F}}_{\text{rms}}=\sqrt{\frac{{\left(\mathrm{Q}{\mathrm{B}}_0\mathrm{c}\right)}^2+{\left(\mathrm{Q}{\mathrm{B}}_1\mathrm{c}\right)}^2}{2}}$
Here$c$is speed of light in vacuum.
$=\sqrt{\frac{{\left({10}^{-4}\times 3\times {10}^{-5}\times 3\times {10}^8\right)}^2+{\left({10}^{-4}\times 2\times {10}^{-6}\times 3\times {10}^8\right)}^2}{2}}$
$=\sqrt{\frac{0.81+0.0036}{2}}=0.6\mathrm{N}$