Physics - EM Waves Question with Solution | TestHub

Given: Amplitude of electric field, $$E_0=4\mathrm{v}/\mathrm{m}$$ Absolute permitivity, $${\epsilon }_0=8.8\times 10^{-12}{\mathrm{c}}^2/\mathrm{N}-{\mathrm{m}}^2$$ Average energy density $u_E=$ ? Applying formula, Average energy density $u_E=\frac{1}{4}{\epsilon }_0{E}^2$ $$\begin{array}{rl}& \Rightarrow u_E=\frac{1}{4}\times 8.8\times 10^{-12}\times (4{)}^2\\ & =35.2\times 10^{-12}\mathrm{J}/{\mathrm{m}}^3\end{array}$$