Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsPotential & potential energyMedium2 minQB

PhysicsMediumnumerical

Passage / Comprehension

Below the fixed end of the insulating horizontal thread, there is a fixed charge A of $20 μ$ C, which is the same as the charge of the small body B of mass $m$ at the end of the thread, as shown in the figure. The body B is released, and when it is at the lowest position, the thread is vertical. Assume that the thread does not strike the fixed charge. The body B comes to a stop at the lowest position.(Take g=10 $\frac{m}{s ^{2}}$ )

What is the initial acceleration(in SI units) of the small body:

Answer:

8.80

Solution:

At horizontal position,

$a_{r} = 0$ .

$m a_{c} = m g - \frac{k Q ^{2}}{r ^{2}} sin 3 7^{\circ}$

$a_{c} = g - \frac{k Q ^{2}}{m r ^{2}} sin 3 7^{\circ} = 8.8 m / s^{2}$

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...