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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsPotential & potential energyMedium2 minQB

PhysicsMediummultiple choice

Two point charges Q and - Q/4 are separated by a distance x. Then

Options:(select one or more)

Answer:

A, B, C

Solution:

Zero potential: $\frac{k Q}{r _{1}} = \frac{k Q /4}{r _{2}} \Rightarrow r_{1} = 4 r_{2}$

Between the charges this gives a point $\frac{x}{5}$ on the left side of $- \frac{Q}{4}$ (B correct); on its right: $x + r_{2} = 4 r_{2} \Rightarrow r_{2} = \frac{x}{3}$ (A correct).

Zero field needs $r_{1} = 2 r_{2}$ ; between the charges both fields point the same way, so the only null point is at distance $x$ on the right of $- \frac{Q}{4}$ (C correct, D wrong).

Subject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: QB

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