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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsPotential & potential energyEasy2 minQB

PhysicsEasysingle choice

If two electric charges q and -2q are placed at distance 6a apart, then locus of point in the plane of charges, where electric potential is zero is : (Take charge q at origin and -2q lies on positive x-axis)

Options:

Answer:

Solution:

$V = \frac{k q}{x ^{2} + y ^{2}} - \frac{2 k q}{( x - 6 a ) ^{2} + y ^{2}} = 0$ .

$(x - 6 a)^{2} + y^{2} = 4 (x^{2} + y^{2})$ .

$x^{2} + y^{2} + 4 a x - 12 a^{2} = 0$ - (B)

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: QB

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