Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsMedium2 minQB

PhysicsMediumsingle choice

In a region of space, the electric field $E = E_{0} x \hat{i} + E_{0} y \hat{j}$ . Consider an imaginary cubical volume of edge 'a' with its edges parallel to the axes of coordinates. Now,

Options:

Answer:

A, B

Solution:

$ϕ = E \cdot A$ $ϕ_{in} = - Ve$ and $ϕ_{out} = + Ve$ $Q_{net} = \frac{q _{in}}{ε _{0}}$ $ϕ_{1} = 0, ϕ_{2} = E_{0} a^{3}, ϕ_{3} = E_{0} a^{3}; ϕ_{4} = 0, ϕ_{5} = 0, ϕ_{6} = 0$ $Q_{net} = ϕ_{1} + ϕ_{2} + ϕ_{3} + ϕ_{4} + ϕ_{5} + ϕ_{6} = 2 E_{0} a^{3} \Rightarrow 2 E_{0} a^{3} = \frac{q _{in}}{ϵ _{0}} \Rightarrow q_{in} = 2 ε_{0} E_{0} a^{3}$

Stream:JEESubject:PhysicsTopic:Electrostatics

⏱ 2mℹ️ Source: QB

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