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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsElectric Field & ForceMedium2 minQB

PhysicsMediumsingle choice

An electron with kinetic energy $K_{1}$ enters between parallel plates of a capacitor at an angle $α$ with the plates. It leaves the plates at angle $β$ with kinetic energy $K_{2} .$ Then the ratio of kinetic energies $K_{1} : K_{2}$ will be :

Options:

Answer:

Solution:

velocity along the plate will not change.

$∴ v_{1} \cos α = v_{2} \cos β$

$\frac{K_{1}}{K_{2}} \Rightarrow \frac{v_{1}^{2}}{v_{2}^{2}} = \frac{\cos^{2} β}{\cos^{2} α}$

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Electric Field & Force

⏱ 2mℹ️ Source: QB

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