Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsMiscellaneousHard2 minQB
PhysicsHardmatching list

Match the entries of List - I with the systems of List - II:

List - I

List - II

(A) Magnitude of angular momentum of system about O increases after the instant shown.

(P) A dipole is hinged on a long smooth fixed horizontal wire. A charge Q (A) is threaded on wire and is free to move on the wire. The system comprises of the dipole and point charge. Gravity is absent.

(B) The net torque on body A is zero about O at the instant shown.

(Q) A system of two charges and (A) of mass m each are connected by a light rod and kept on smooth level ground. An external uniform electric field is applied as shown. Gravity is present.

(C) The net force on negative charge increases in magnitude after the instant shown.

(R) An electron (A) is revolving about a fixed proton in anticlockwise direction. The system comprises of the electron and proton. Gravity is absent.

(D) Mechanical energy of the system increases after the instant shown.

(S) System consists of a particle (A) of mass m and charge . It is projected from level ground in presence of constant electric field in vertically upward direction. Gravity is present. (Ignore potential energy of external electrical field.)

 

(T) System consists of a uniform ring and particle (A) of mass m and charge on its circumference as shown. The ring is in pure rolling on a sufficiently rough horizontal surface. Gravity is present.

Options:

Answer:
B
Solution:

(P) The charge Q is on the dipole's equatorial line, so the electric force on it is vertical and balanced by the wire's normal: net force zero ⇒ torque about O zero - (B). The dipole starts rotating; its angular speed grows from zero, so angular momentum about O grows (A) and the centripetal force on grows from zero (C). Only internal forces: energy constant (D wrong).

(Q) Body A is the charge at O: all forces on it act at O, torque about O is zero - (B). The charge lifts off (), the rod tilts and later drags : the net force on the negative charge grows from zero (C); the angular momentum about O grows as speeds up (A); the external field does positive work: mechanical energy increases (D).

(R) Isolated electron-proton: central force. Torque on the electron about O is zero (B); L, force magnitude and energy are all constant (A, C, D wrong).

(S) Constant net force downward on : torque about O grows as x grows, so increases (A); net force constant (C wrong); the electric force does negative work as the particle rises, so mechanical energy decreases (D wrong); torque nonzero (B wrong).

(T) Pure rolling, no external field: energy conserved (D wrong); gravity on the particle gives nonzero torque about O (B wrong); nothing drives L or the force to grow at the instant shown (A, C wrong).

Hence A - PQS, B - PRS, C - PQ, D - Q.

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Miscellaneous
⏱ 2mℹ️ Source: QB

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