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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsConductorMedium2 minQB

PhysicsMediuminteger

A spherical shell has uniform charge density $8.8 \times 1 0^{- 11} C / m^{2}$ . If a pin hole is made in the surface of the shell then find the electric field in the hole in N/C. (Take $ϵ_{0} = 8.8 \times 1 0^{- 12}$ S.I. units)

Answer:

Solution:

Field just outside the shell is $\frac{σ}{ε _{0}}$ ; the hole's own contribution is removed, leaving

$E = \frac{σ}{2 ε _{0}} = \frac{8.8 \times 1 0 ^{- 11}}{2 \times 8.8 \times 1 0 ^{- 12}} = 5 N / C$ .

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Conductor

⏱ 2mℹ️ Source: QB

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