Start Free Mock LoginAlready registered? Login here

Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsRelation between field & potentialMedium2 minQB

PhysicsMediuminteger

Figure shows equipotential lines in x-y plane. Distances AB, BC and CD are all equal to 4 cm. Find the magnitude of electric field (in V/cm) in the region.

Answer:

Solution:

The perpendicular gap between successive equipotential lines is $d = 4 sin 3 0^{\circ} = 2$ cm, with $Δ V = 10$ V between them.

$E = \frac{Δ V}{d} = \frac{10}{2} = 5$ V/cm.

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Relation between field & potential

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...