Two bodies A and B each of mass 'm' and carrying charge 'Q' are rotating with constant speed 'v' in a circle of radius r /2 on a smooth horizontal surface and are connect

Question

Two bodies A and B each of mass 'm' and carrying charge 'Q' are rotating with constant speed 'v' in a circle of radius r /2 on a smooth horizontal surface and are connected by spring of natural length l 0 ​ and spring constant ' k ' the total energy of the system is.

TestHub · Accepted Answer

Total energy = KE + electrostatic PE + spring PE.

$E = \frac{1}{2} m v^{2} + \frac{1}{2} m v^{2} + \frac{1}{4 π ε _{0}} \frac{Q ^{2}}{r} + \frac{1}{2} k (r - l_{0})^{2}$ .

$E = m v^{2} + \frac{Q ^{2}}{4 π ε _{0} r} + \frac{1}{2} k (r - l_{0})^{2}$ - none of (A), (B), (C) matches - (D)

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