Two smooth spherical non conducting shells each of radius R having uniformly distributed charge Q and Q on their surfaces are released on a smooth non-conducting surface when the distance between thei

Question

Two smooth spherical non conducting shells each of radius R having uniformly distributed charge Q and Q on their surfaces are released on a smooth non-conducting surface when the distance between their centres is 5 R . The mass of A is m and that of B is 2 m . The speed of A just before A and B collide is :[Neglect gravitational interaction] $(K = \frac{1}{4 π ε _{0}})$

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Answer:

A

Solution:

$mv = 2 m (v^{'})$ $\frac{K Q ( - Q )}{5 R} = \frac{K Q ( - Q )}{2 R} + \frac{1}{2} m v^{2} + \frac{1}{2} (2 m) (v^{'})^{2} \Rightarrow v = \frac{2 K Q ^{2}}{5 m R}$

TestHub · Accepted Answer

mv = 2 m ( v ′ ) 5 R K Q ( − Q ) ​ = 2 R K Q ( − Q ) ​ + 2 1 ​ m v 2 + 2 1 ​ ( 2 m ) ( v ′ ) 2 ⇒ v = 5 m R 2 K Q 2 ​ ​

Physics - Electrostatics Question with Solution | TestHub

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Doubts & Discussion

JEE Advanced (2028)