Physics - Electrostatics Question with Solution | TestHub

In free space, a particle A of charge $1\mu \mathrm{C}$ is held fixed at a point P. Another particle B of the same charge and mass $4\mathrm{mg}$ is kept at a distance of 1 mm from P . if B is released, then its velocity at a distance of 9 mm from P is :

$\left[\text{ Take }\frac{1}{4\pi {\epsilon }_0}=9\times 10^9{\mathrm{Nm}}^2{\mathrm{C}}^{-2}\right]$