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PhysicsElectrostaticsElectric Field & FluxMedium2 minPYQ_2025

PhysicsMediumsingle choice

Two point charges $- 4 μ c$ and $4 μ c$ , constituting an electric dipole, are placed at $(- 9, 0, 0) cm$ and $(9, 0, 0) cm$ in a uniform electric field of strength $1 0^{4} NC^{- 1}$ . The work done on the dipole in rotating it from the equilibrium through $18 0^{\circ}$ is :

Options:

Answer:

Solution:

$U = - PE cos θ w_{ext} = Δ U = U_{f} - U_{i} = - PE cos 18 0^{\circ} + PE cos 0^{\circ} w_{ext} = 2 PE = 2 \times (4 \times 1 0^{- 6}) (18) \times 1 0^{4} = 144 \times 1 0^{- 2} = 14.4 mJ$

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Electric Field & Flux

⏱ 2mℹ️ Source: PYQ_2025

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