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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsPotential & potential energyMedium2 minPYQ_2025

PhysicsMediumsingle choice

Two charges $+ q$ and $- q$ are placed at points $A$ and $B$ respectively which are at a distance $2 L$ apart. $C$ is the mid point of $A$ and $B$ . The workdone in moving a charge $+ Q$ along the semicircle $CSD (W_{1})$ and along the line $CBD (W_{2})$ are

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Answer:

Solution:

$W_{CS D} = Q (V_{D A} - V_{C A}) = \frac{Qq}{4 π ϵ _{0} L} [\frac{1}{3} - 1] = \frac{- 2 Qq}{12 π ϵ _{0} L} = \frac{- Qq}{6 π ϵ _{0} L} = W_{CB D} W_{CB D} = W_{CS D} path independent$

Stream:WBJEESubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: PYQ_2025

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