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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsPotential & potential energyEasy2 minPYQ_2024

PhysicsEasysingle choice

A thin spherical shell is charged by some source. The potential difference between the two points $C$ and $P$ (in V ) shown in the figure is: (Take $\frac{1}{4 π ε _{0}} = 9 \times 1 0^{9}$ SI units)
NEET 2024

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Solution:

For uniformly charged spherical shell, $V = \frac{k q}{R} (For r \leq R) ∴ V_{C} = V_{P} V_{C} - V_{P} = Zero$

Stream:NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: PYQ_2024

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